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Wire Cross-Section • Moc w kW

Oblicz przekrój przewodu with Moc w kW

Choose system type and material, enter power, voltage, cos φ and cable length.

Wartości obliczeń

Uwaga: To obliczenie jest technicznie poprawnym uproszczeniem typowym dla kalkulatorów online. Przy doborze praktycznym trzeba również sprawdzić normy, sposób ułożenia, temperaturę, grupowanie, zabezpieczenia, typ kabla i dane producenta.

Zastosowany wzór

Depending on your selection, the calculator uses the correct single-phase or three-phase formula with cos φ.

Three-phase: I = P / (√3 × U × cos φ)

Single-phase: I = P / (U × cos φ)

A = voltage drop formula depending on system type, cable length and material conductivity.

Practical guidance

Use the general cable calculator with active power

This page compares current type and conductor material. It first derives current, then a voltage-drop cross-section.

Input values explained

Prąd type
The current type determines whether the calculation uses factor 2 for outgoing and return conductors or √3 for balanced three-phase power.
Conductor material
Copper and aluminium have different conductivity. Aluminium generally requires a larger cross-section under otherwise equal conditions.
Moc in kilowatts
Enter the electrical active power in kW. One kW equals 1,000 W; motor output power and electrical input power are not necessarily the same.
Cable length
Enter the one-way distance from supply point to load. The required return path is already represented by the selected formula.
Napięcie
Match the voltage to the selected electrical system. Single-phase calculations use line-to-neutral voltage, while three-phase calculations use voltage between two line conductors.
Moc factor cos φ
cos φ is the ratio of active to apparent power. It is close to 1 for resistive heating loads; use the data-sheet value for motors and transformers.
Permitted voltage drop
This percentage limits the calculated voltage loss. It is a design assumption and must suit the circuit and applicable requirements.
Conductivity κ
κ is the calculation value for the conductor material. Common approximations are 58 for copper and 37 for aluminium; heating increases actual resistance.

Example: 11 kW three-phase copper

At 400 V, 11 kW, cos φ 0.90, 25 m and 3%, current is about 17.64 A.

A = (√3 × 25 × 17.64 × 0.90) ÷ (58 × 12) ≈ 0.99 mm²

The next listed size is 1.5 mm² for voltage drop. Real ampacity may require a larger conductor.

A comparison, not approval

The controls demonstrate the effect of material and system, but the output is not a complete installation design.

Calculation limits

  • Cable type, reference method and grouping are unknown.
  • Fault protection and statutory minimum requirements need separate checks.